4x^2-16x+16=25

Solution for 4x^2-16x+16=25 equation:

4x^2-16x+16=25

We move all terms to the left:

4x^2-16x+16-(25)=0

We add all the numbers together, and all the variables

4x^2-16x-9=0

a = 4; b = -16; c = -9;
Δ = b2-4ac
Δ = -162-4·4·(-9)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*4}=\frac{-4}{8}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*4}=\frac{36}{8}
=4+1/2
$